Introduction
In the Factorization Method, we factorize the quadratic equation and put each factor equal to zero and then find the values of x. These values of x are the solution of the quadratic equation and are called the roots of the quadratic equation.
This can be understood by the following examples.
Examples
Example – 1) Find the roots of the quadratic equation x2 + 5x + 6 = 0 by factorization method.
Solution – given equation x2 + 5x + 6 = 0
Step (1) Comparing the equation with the standard form ax2 + bx + c = 0
a = 1, b = 5, c = 6
We take a⨯c = 1⨯6 = 6 and b = 5
Step (2) Now, we have to take two numeric values so that their sum should be equal to b i.e., 5 and their multiplication should be equal to a⨯c i.e., 6. So, we take the numbers 2 and 3.
Note – if it is difficult to find the two numeric values, we can factorize the term a⨯c and make pair to get it easily.
Step (3) Now check
2+3 = 5 and 2⨯3 = 6 (these values satisfy)
Step (4) Now, break the middle term of equation x2 + 5x + 6 with the help of the above sum 2+3 = 5
x2 + (2+3)x + 6 = 0
x2 + 2x + 3x + 6 = 0
Step (5) Now take common terms out from the first two terms and last two terms.
x(x + 2) + 3(x+2) = 0
(x+2) is again a common term so,
(x+2) (x+3) = 0
Step (6) Now, by putting each factor equal to zero.
(x+2) = 0 and (x+3) = 0
x = -2 and x = -3 Ans.
Both the values of x are the solution of the given quadratic equation and are called the roots of this equation.
We can check our answer by putting the values of x in the given quadratic equation.
x2 + 5x + 6 = 0
at x = -2,
(-2)2 + 5(-2) + 6 = 0
4 – 10 + 6 = 0
– 6 + 6 = 0
0 = 0
LHS = RHS
at x = -3,
(-3)2 + 5(-3) + 6 = 0
9 – 15 + 6 = 0
– 6 + 6 = 0
0 = 0
LHS = RHS
At both values, LHS = RHS which means our answer is correct.
Example – 2) Find the roots of the quadratic equation 2x2 – 5x + 3 = 0 by factorization method.
Solution – 2x2 – 5x + 3 = 0 Here, a⨯c = 2⨯3 = 6 and b = -5
2x2 – (2+3)x + 3 = 0 two numeric values -2 and -3
2x2 – 2x – 3x + 3 = 0 -2⨯(-3) = 6 and -2 + (-3) = -2 – 3 = -5
2x(x-1) -3(x-1) = 0
(x-1) (2x-3) = 0
(x-1) = 0 and (2x-3) = 0
x = 1 and x = 3/2
Thus, the roots of the quadratic equation 2x2 – 5x + 3 = 0 are x = 1 and x = 3/2. Ans.